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11x^2+16x-12=0
a = 11; b = 16; c = -12;
Δ = b2-4ac
Δ = 162-4·11·(-12)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-28}{2*11}=\frac{-44}{22} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+28}{2*11}=\frac{12}{22} =6/11 $
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